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Physics Worksheet

🎸 Standing Waves

Chapter: Waves · Level ★★☆ · Time: 30 min
SCORE___ / 20
NameClassDate
After this worksheet you can
Understand: How Standing Waves FormUnderstand: Nodes and AntinodesUnderstand: Standing Waves on a String (Fixed at Both Ends)Understand: Fundamental Frequency and Harmonics

🧠 Section A · Concept Check ● BEGINNER 4 × 1 = 4

1A string of length 1.5m is fixed at both ends. Find the fundamental wavelength.
2A string's fundamental frequency is 220Hz. Find its 4th harmonic frequency.
3A string of length 2m has a standing wave with n=2. Find its wavelength.
4Why do only specific wavelengths 'fit' on a string fixed at both ends?
A standing wave pattern with nodes and antinodes

🧮 Section B · Problem Solving ● INTERMEDIATE 4 × 3 = 12

5A guitar string produces a fundamental frequency of 330Hz. Find its 5th harmonic.
6Why do musical instruments produce specific, distinguishable pitches rather than random noise?
7How many nodes does the fundamental (n=1) standing wave have on a string fixed at both ends (not counting the two fixed ends, which are also nodes)?
8How many antinodes does the fundamental (n=1) standing wave have?

🚀 Section C · Challenge ● CHALLENGE 2 × 2 = 4

9A string has fundamental frequency 150Hz. Is 450Hz one of its harmonics? If so, which one?
10Why is understanding standing waves essential for designing musical instruments?
💭 Reflection — the most useful thing I learned:
A ___/4   B ___/12   C ___/4   Total ___/20 Teacher's Signature Parent's Signature
✂ answer key — fold or cut before handing out

1 = 3m   2 = 880Hz   3 = lambda_2=2*2/2=2m   4 = Both ends must be nodes (fixed, zero displacement), which only occurs for wavelengths that divide evenly into twice the string length  |  5 = 1650Hz   6 = Standing waves only form at specific resonant frequencies (harmonics) determined by the instrument's length and boundary conditions   7 = 0 additional nodes between the ends (just the two endpoints)   8 = 1 antinode (in the middle)  |  9 = Yes, the 3rd harmonic (450=3*150)   10 = It determines exactly what pitches (frequencies) an instrument can naturally produce based on its physical dimensions

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