BitWithBite
Physics Worksheet
💨 Gas Laws
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After this worksheet you can
Understand: Boyle's LawUnderstand: Charles's LawUnderstand: Gay-Lussac's LawUnderstand: The Combined Gas Law🧠 Section A · Concept Check ● BEGINNER 4 × 1 = 4
1A gas has volume 8L at pressure 2 atm. Find volume at 4 atm (Boyle's Law).
2A gas has volume 5L at 250K. Find volume at 500K (Charles's Law).
3A gas has pressure 2 atm at 300K. Find its pressure at 600K (Gay-Lussac's Law, constant volume).
4A gas has P1=2atm, V1=6L, T1=300K. Find P2 if V2=3L and T2=600K.
🧮 Section B · Problem Solving ● INTERMEDIATE 4 × 3 = 12
5Why does a sealed bag of chips appear to puff up at high altitude?
6Why does a balloon shrink when placed in a freezer?
7Find n if a gas has P=1atm (≈101325 Pa), V=0.0224 m^3, T=273K (R=8.314).
8Why does a car tire's pressure increase after driving for a while (constant volume)?
🚀 Section C · Challenge ● CHALLENGE 2 × 2 = 4
9What must stay constant to apply Boyle's Law directly?
10What must stay constant to apply Charles's Law directly?
💭 Reflection — the most useful thing I learned:
A ___/4 B ___/12 C ___/4 Total ___/20
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✂ answer key — fold or cut before handing out
1 = 16=4*V2, V2=4L 2 = 5/250=V2/500, V2=10L 3 = 2/300=P2/600, P2=4atm 4 = (2*6)/300=(P2*3)/600, 0.04=P2/200, P2=8atm | 5 = Lower outside atmospheric pressure allows the gas inside the bag to expand (Boyle's Law), since the bag's internal pressure is now higher relative to the surroundings 6 = Lower temperature reduces the gas's volume at constant pressure (Charles's Law) 7 = n=PV/RT=101325*0.0224/(8.314*273)≈1 mol 8 = Friction heats the tire, raising the gas temperature, which increases pressure at constant volume (Gay-Lussac's Law) | 9 = Temperature (and amount of gas) 10 = Pressure (and amount of gas)