BitWithBite
Physics Worksheet
🚗 Motion in One Dimension
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After this worksheet you can
Understand: Position, Displacement, and DistanceUnderstand: Speed vs. VelocityUnderstand: AccelerationUnderstand: The Equations of Motion (Constant Acceleration)📚 Quick Recap
The simplest kind of motion happens along a single straight line — mastering it lays the groundwork for understanding motion in two and three dimensions.
🧠 Section A · Concept Check ● BEGINNER 4 × 1 = 4
1A car accelerates from rest at 5 m/s^2 for 6s. Find final velocity.
2A car at 10 m/s accelerates at 3 m/s^2 for 4s. Find distance traveled.
3A car accelerates from 4 m/s to 20 m/s over 80m. Find acceleration.
4What does the slope of a velocity-time graph represent?
🧮 Section B · Problem Solving ● INTERMEDIATE 4 × 3 = 12
5A ball is dropped and falls for 3s with acceleration 10 m/s^2 (approx gravity). Find its velocity.
6Using the same ball, find the distance fallen.
7If a car's velocity-time graph is a flat horizontal line, what does that indicate?
8A car decelerates from 20 m/s to 0 m/s in 4s. Find its acceleration.
🚀 Section C · Challenge ● CHALLENGE 2 × 2 = 4
9Using the previous problem, find the distance traveled while decelerating.
10Why is distance always greater than or equal to the magnitude of displacement?
💭 Reflection — the most useful thing I learned:
A ___/4 B ___/12 C ___/4 Total ___/20
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✂ answer key — fold or cut before handing out
1 = 30 m/s 2 = s=10*4+0.5*3*16=40+24=64m 3 = v^2=u^2+2as: 400=16+160a, a=2.4 m/s^2 4 = Acceleration | 5 = v=0+10*3=30 m/s 6 = s=0+0.5*10*9=45m 7 = Constant velocity (zero acceleration) 8 = a=(0-20)/4=-5 m/s^2 | 9 = s=20*4+0.5*(-5)*16=80-40=40m 10 = Distance measures the total path traveled, while displacement measures only the straight-line change in position, which can never exceed the path length