1 = 40 N*s 2 = F*2=3*6=18, F=9N 3 = F*0.01=0.15*40=6, F=600N 4 = It extends the time of the catch, reducing the average force for the same change in the ball's momentum | 5 = The total impulse delivered 6 = F*0.2=500*10=5000, F=25000N 7 = It increases significantly, since force and time are inversely related for a fixed impulse 8 = 16=2*v, v=8 m/s | 9 = They extend the time of impact, reducing the peak force experienced for a given momentum change 10 = F=4/0.5=8N