01 Key Concepts
Projectile Motion Setup
Combines constant horizontal velocity (no horizontal acceleration) with constant vertical acceleration due to gravity (g โ 9.8 m/s^2 downward).
Horizontal Motion
Since there's no horizontal force (ignoring air resistance), horizontal velocity stays constant throughout the flight: x = vx*t.
Vertical Motion
Vertical velocity changes due to gravity: vy = vy0 - g*t, and vertical position follows y = vy0*t - (1/2)*g*t^2.
Time of Flight
For a projectile launched and landing at the same height, time of flight = 2*vy0/g.
Maximum Height and Range
Maximum height = vy0^2/(2g). Range (horizontal distance) = vx*(time of flight), often written as R = v^2*sin(2*theta)/g for launch speed v and angle theta.
02 Key Formulas
- Time of flight (same launch/landing height) = 2*vy0/g
- Maximum height = vy0^2 / (2g)
- Range = v^2 * sin(2*theta) / g
03 Solved Examples
- Horizontal velocity stays constant: x = vx*t = 10*2.
- At maximum height, vertical velocity = 0.
- Using vy=vy0-g*t: 0 = 20-10t, so t=20/10.
- Apply R = v^2*sin(2*theta)/g = 30^2*sin(90ยฐ)/10.
- = 900*1/10.
04 Practice Questions
๐ Projectile Motion โ Downloadable Worksheet
10 questions with a full answer key. Grab the PDF to print, or try the interactive version in your browser.