๐Ÿ“˜ Lesson 6 of 19 ยท Mechanics

๐ŸŽฏ Projectile Motion

A projectile is any object launched into the air and left to move under gravity alone โ€” its path traces a graceful curve called a parabola.

Course progress: 32%

01 Key Concepts

Projectile Motion Setup

Combines constant horizontal velocity (no horizontal acceleration) with constant vertical acceleration due to gravity (g โ‰ˆ 9.8 m/s^2 downward).

Horizontal Motion

Since there's no horizontal force (ignoring air resistance), horizontal velocity stays constant throughout the flight: x = vx*t.

Vertical Motion

Vertical velocity changes due to gravity: vy = vy0 - g*t, and vertical position follows y = vy0*t - (1/2)*g*t^2.

Time of Flight

For a projectile launched and landing at the same height, time of flight = 2*vy0/g.

Maximum Height and Range

Maximum height = vy0^2/(2g). Range (horizontal distance) = vx*(time of flight), often written as R = v^2*sin(2*theta)/g for launch speed v and angle theta.

A projectile follows a parabolic path

02 Key Formulas

03 Solved Examples

Example 1 A ball is thrown horizontally at 10 m/s from a height where it takes 2 seconds to hit the ground. Find the horizontal distance traveled.
  1. Horizontal velocity stays constant: x = vx*t = 10*2.
Answer: 20 meters
Example 2 A projectile is launched straight up at 20 m/s (g=10 m/s^2). Find the time to reach maximum height.
  1. At maximum height, vertical velocity = 0.
  2. Using vy=vy0-g*t: 0 = 20-10t, so t=20/10.
Answer: 2 seconds
Example 3 A projectile is launched at 30 m/s at a 45ยฐ angle (g=10 m/s^2, sin(90ยฐ)=1). Find its range.
  1. Apply R = v^2*sin(2*theta)/g = 30^2*sin(90ยฐ)/10.
  2. = 900*1/10.
Answer: 90 meters

04 Practice Questions

1A ball is thrown horizontally at 5 m/s and falls for 3s. Find horizontal distance.
15 m
2A projectile is launched straight up at 30 m/s (g=10). Find time to max height.
3s
3Find the max height for vy0=20 m/s (g=10).
20 m (using vy0^2/(2g)=400/20)
4What is the horizontal acceleration of a projectile (ignoring air resistance)?
0 (horizontal velocity stays constant)
5What is the approximate value of g used in these problems?
9.8 m/s^2 (or approximated as 10 m/s^2)

๐Ÿ“„ Projectile Motion โ€” Downloadable Worksheet

10 questions with a full answer key. Grab the PDF to print, or try the interactive version in your browser.