BitWithBite
Mathematics Worksheet
🔀 Conditional Probability
SCORE___ / 20
NameClassDate
After this worksheet you can
Use P(A|B) = P(A ∩ B)/P(B).Handle draws without replacement.Use independence: P(A ∩ B) = P(A)P(B).Interpret conditional probabilities.📚 Quick Recap
Conditional probability answers the question: given that something has already happened, how likely is something else? It updates our probability estimate using new information.
🧠 Section A · Concept Check ● BEGINNER 4 × 1 = 4
1A die is rolled. P(number > 3 | number is odd) =:
2A bag has 3 red and 7 blue balls. P(2 blue, no replacement) =:
3If P(A)=0.3, P(B)=0.6 and events are independent, P(A ∩ B) =:
4If P(A ∩ B)=0.15 and P(B)=0.3, then P(A|B) =:
🧮 Section B · Problem Solving ● INTERMEDIATE 2 + 3×3 = 11
5P(A | B) = P(A ∩ B) / .
6For independent events, P(A ∩ B) = P(A) × .
7A die is rolled. Find P(number > 3 | number is odd).
8A bag has 3 red and 7 blue balls. Find P(drawing 2 blue without replacement).
9If P(A)=0.3, P(B)=0.6, independent. Find P(A and B).
🚀 Section C · Challenge ● CHALLENGE 5
10If P(A and B)=0.15 and P(B)=0.3, find P(A|B).
💭 Reflection — the most useful thing I learned:
A ___/4 B ___/11 C ___/5 Total ___/20
Teacher's Signature
Parent's Signature
✂ answer key — fold or cut before handing out
1-A 2-A 3-A 4-A | 5 P(B) 6 P(B) 7 = P(A∩B)=1/6, P(B)=1/2, so P(A|B)=1/3 8 = (7/10)(6/9) = 7/15 9 = 0.18 | 10 = 0.5